{"id":83,"date":"2014-01-01T19:57:15","date_gmt":"2014-01-01T19:57:15","guid":{"rendered":"http:\/\/www.eversholt.org.uk\/blog\/?p=83"},"modified":"2014-01-01T19:57:15","modified_gmt":"2014-01-01T19:57:15","slug":"rising-gate-geometry-2-wonkish","status":"publish","type":"post","link":"https:\/\/www.eversholt.org.uk\/blog\/rising-gate-geometry-2-wonkish\/","title":{"rendered":"Rising Gate Geometry 2 (Wonkish)"},"content":{"rendered":"<p>The <a title=\"Rising Gate Geometry (Wonkish)\" href=\"http:\/\/www.eversholt.org.uk\/blog\/?p=75\">previous post<\/a> demonstrated that gate hinges should lie in a vertical plane normal to the bisector of the open and closed gate positions. Here&#8217;s the plan view of the hinges in the open position: (click for a bigger version)<\/p>\n<div id=\"attachment_79\" style=\"width: 310px\" class=\"wp-caption alignnone\"><a href=\"http:\/\/www.eversholt.org.uk\/blog\/wp-content\/uploads\/2014\/01\/gate5-1.png\"><img loading=\"lazy\" decoding=\"async\" aria-describedby=\"caption-attachment-79\" class=\"size-medium wp-image-79\" alt=\"gate5-1\" src=\"http:\/\/www.eversholt.org.uk\/blog\/wp-content\/uploads\/2014\/01\/gate5-1-300x229.png\" width=\"300\" height=\"229\" srcset=\"https:\/\/www.eversholt.org.uk\/blog\/wp-content\/uploads\/2014\/01\/gate5-1-300x229.png 300w, https:\/\/www.eversholt.org.uk\/blog\/wp-content\/uploads\/2014\/01\/gate5-1-1024x784.png 1024w, https:\/\/www.eversholt.org.uk\/blog\/wp-content\/uploads\/2014\/01\/gate5-1-624x478.png 624w, https:\/\/www.eversholt.org.uk\/blog\/wp-content\/uploads\/2014\/01\/gate5-1.png 1266w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/a><p id=\"caption-attachment-79\" class=\"wp-caption-text\">Plan view of hinges, gate fully open<\/p><\/div>\n<p>Triangles <span style=\"color: #0000ff;\">BFG<\/span> and <span style=\"color: #0000ff;\">BFK<\/span>, lying in the horizontal plane, are mirror images. So, length <span style=\"color: #0000ff;\">FK<\/span> must be <span style=\"color: #0000ff;\">O<sub>NS<\/sub><\/span><\/p>\n<p><a href=\"http:\/\/www.eversholt.org.uk\/blog\/wp-content\/uploads\/2014\/01\/gate7-1.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-medium wp-image-84\" alt=\"gate7-1\" src=\"http:\/\/www.eversholt.org.uk\/blog\/wp-content\/uploads\/2014\/01\/gate7-1-300x267.png\" width=\"300\" height=\"267\" srcset=\"https:\/\/www.eversholt.org.uk\/blog\/wp-content\/uploads\/2014\/01\/gate7-1-300x267.png 300w, https:\/\/www.eversholt.org.uk\/blog\/wp-content\/uploads\/2014\/01\/gate7-1-624x557.png 624w, https:\/\/www.eversholt.org.uk\/blog\/wp-content\/uploads\/2014\/01\/gate7-1.png 936w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/a><\/p>\n<p>&nbsp;<\/p>\n<p>The points labelled here are exactly the same as the ones in the previous diagram. Length <span style=\"color: #0000ff;\">FK<\/span> in the horizontal <span style=\"color: #0000ff;\">BFK<\/span> plane is <span style=\"color: #0000ff;\">O<sub>NS<\/sub><\/span>, because triangle <span style=\"color: #0000ff;\">BFK<\/span> and <span style=\"color: #0000ff;\">BFG<\/span> are mirror images. Length <span style=\"color: #0000ff;\">KM<\/span> is also <span style=\"color: #0000ff;\">O<sub>NS<\/sub><\/span>, because that&#8217;s how we made the spacer for the gate. Triangles <span style=\"color: #0000ff;\">AFK<\/span> and <span style=\"color: #0000ff;\">AMK<\/span> are therefore mirror images, because they are both right triangles, they share a hypotenuse and have side <span style=\"color: #0000ff;\">KM<\/span> equal to side <span style=\"color: #0000ff;\">KF<\/span>. So, angle <span style=\"color: #0000ff;\">KAF<\/span> is equal to angle <span style=\"color: #0000ff;\">KAM<\/span>. Let&#8217;s call this angle\u00a0<span style=\"color: #0000ff;\">\u03b8<\/span>. And, call distance <span style=\"color: #0000ff;\">AF<\/span>, the vertical distance between the hinges, <span style=\"color: #0000ff;\">O<sub>UD<\/sub><\/span>.<\/p>\n<p style=\"padding-left: 30px;\">tan\u00a0<span style=\"color: #0000ff;\">\u03b8<\/span> = <span style=\"color: #0000ff;\">KF<\/span> \/ <span style=\"color: #0000ff;\">AF<\/span> = <span style=\"color: #0000ff;\">O<sub>NS<\/sub><\/span> \/ <span style=\"color: #0000ff;\">O<sub>UD<\/sub><\/span><\/p>\n<p style=\"padding-left: 30px;\"><span style=\"color: #0000ff;\">\u03b8<\/span> = tan<sup>-1<\/sup> (<span style=\"color: #0000ff;\">O<sub>NS<\/sub><\/span> \/ <span style=\"color: #0000ff;\">O<sub>UD<\/sub><\/span>)<\/p>\n<p>Here&#8217;s how the gate looks when fully open.<\/p>\n<p><a href=\"http:\/\/www.eversholt.org.uk\/blog\/wp-content\/uploads\/2014\/01\/gate8.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-medium wp-image-85\" alt=\"gate8\" src=\"http:\/\/www.eversholt.org.uk\/blog\/wp-content\/uploads\/2014\/01\/gate8-300x270.png\" width=\"300\" height=\"270\" srcset=\"https:\/\/www.eversholt.org.uk\/blog\/wp-content\/uploads\/2014\/01\/gate8-300x270.png 300w, https:\/\/www.eversholt.org.uk\/blog\/wp-content\/uploads\/2014\/01\/gate8-624x563.png 624w, https:\/\/www.eversholt.org.uk\/blog\/wp-content\/uploads\/2014\/01\/gate8.png 938w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/a><\/p>\n<p>&nbsp;<\/p>\n<p>The gate rises up at an angle 2<span style=\"color: #0000ff;\">\u03b8<\/span> from the horizontal. The effective length of the gate, <span style=\"color: #0000ff;\">JK<\/span>, is <span style=\"color: #0000ff;\">O<sub>GATE<\/sub><\/span> + <span style=\"color: #0000ff;\">O<sub>NS<\/sub><\/span>.<\/p>\n<p style=\"padding-left: 30px;\"><span style=\"color: #0000ff;\">JN<\/span> \/ <span style=\"color: #0000ff;\">JK<\/span> = sin (2<span style=\"color: #0000ff;\">\u03b8<\/span>)<\/p>\n<p style=\"padding-left: 30px;\"><span style=\"color: #0000ff;\">Rise<\/span> = <span style=\"color: #0000ff;\">JN<\/span> = (<span style=\"color: #0000ff;\">O<sub>GATE<\/sub><\/span> + <span style=\"color: #0000ff;\">O<sub>NS<\/sub><\/span>) * sin (2<span style=\"color: #0000ff;\">\u03b8<\/span>)<\/p>\n<p style=\"padding-left: 30px;\"><span style=\"color: #0000ff;\">Rise<\/span> = (<span style=\"color: #0000ff;\">O<sub>GATE<\/sub><\/span> + <span style=\"color: #0000ff;\">O<sub>NS<\/sub><\/span>) * sin(2 *\u00a0tan-1\u00a0(<span style=\"color: #0000ff;\">O<sub>NS<\/sub><\/span>\u00a0\/ <span style=\"color: #0000ff;\">O<sub>UD<\/sub><\/span>)) \u00a0 \u2666 Equation 2<br \/>\n<span style=\"color: #999999;\"><em><small>Oddly, this doesn&#8217;t depend on\u00a0\u03b2. Is that right?<\/small><\/em><\/span><\/p>\n<p>So now I have some equations for the variables <span style=\"color: #0000ff;\">O<sub>NS<\/sub><\/span> and <span style=\"color: #0000ff;\">O<sub>WE<\/sub><\/span>. Here are the parameters fixed by the requirements of the gate design:<\/p>\n<table border=\"0\">\n<tbody>\n<tr>\n<td>Symbol<\/td>\n<td>Meaning<\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #0000ff;\">O<sub>UD<\/sub><\/span><\/td>\n<td>Vertical pitch between gate hinges<\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #0000ff;\">O<sub>GATE<\/sub><\/span><\/td>\n<td>Width of gate when closed, measured from centre of top hinge pin to outside edge of gate<\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #0000ff;\">Rise<\/span><\/td>\n<td>Required Rise of gate when fully open<\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #0000ff;\">\u03b2<\/span><\/td>\n<td>Angle between gate open and gate closed<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Here are the parameters I&#8217;m trying to determine:<\/p>\n<table border=\"0\">\n<tbody>\n<tr>\n<td>Symbol<\/td>\n<td>Meaning<\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #0000ff;\">O<sub>NS<\/sub><\/span><\/td>\n<td>Offset of bottom hinge parallel to the gate<\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #0000ff;\">O<sub>WE<\/sub><\/span><\/td>\n<td>Outset of bottom hinge at right angles to the gate<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>And here are my equations:<\/p>\n<p style=\"padding-left: 30px;\"><span style=\"color: #0000ff;\">O<sub>WE<\/sub><\/span>\u00a0=\u00a0<span style=\"color: #0000ff;\">O<sub>NS<\/sub><\/span>\u00a0* tan (90\u00b0 &#8211;\u00a0<span style=\"color: #0000ff;\">\u03b2<\/span>\/2) \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0\u2666 Equation 1, from <a title=\"Rising Gate Geometry (Wonkish)\" href=\"http:\/\/www.eversholt.org.uk\/blog\/?p=75\">previous post<\/a><\/p>\n<p style=\"padding-left: 30px;\"><span style=\"color: #0000ff;\">Rise<\/span> = (<span style=\"color: #0000ff;\">O<sub>GATE<\/sub><\/span> + <span style=\"color: #0000ff;\">O<sub>NS<\/sub><\/span>) * sin(2 *\u00a0tan-1\u00a0(<span style=\"color: #0000ff;\">O<sub>NS<\/sub><\/span>\u00a0\/ <span style=\"color: #0000ff;\">O<sub>UD<\/sub><\/span>)) \u00a0 \u00a0\u00a0\u2666 Equation 2<\/p>\n<p>I don&#8217;t actually know of a symbolic solution of (2) for <span style=\"color: #0000ff;\">O<sub>NS<\/sub><\/span>. Fortunately, that doesn&#8217;t stop me solving it numerically, which will come in a post real soon now.<\/p>\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>The previous post demonstrated that gate hinges should lie in a vertical plane normal to the bisector of the open and closed gate positions. Here&#8217;s the plan view of the hinges in the open position: (click for a bigger version) Triangles BFG and BFK, lying in the horizontal plane, are mirror images. So, length FK [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[4,5],"tags":[],"class_list":["post-83","post","type-post","status-publish","format-standard","hentry","category-rising-gates","category-wonkish"],"jetpack_featured_media_url":"","jetpack_sharing_enabled":true,"_links":{"self":[{"href":"https:\/\/www.eversholt.org.uk\/blog\/wp-json\/wp\/v2\/posts\/83","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.eversholt.org.uk\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.eversholt.org.uk\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.eversholt.org.uk\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.eversholt.org.uk\/blog\/wp-json\/wp\/v2\/comments?post=83"}],"version-history":[{"count":1,"href":"https:\/\/www.eversholt.org.uk\/blog\/wp-json\/wp\/v2\/posts\/83\/revisions"}],"predecessor-version":[{"id":88,"href":"https:\/\/www.eversholt.org.uk\/blog\/wp-json\/wp\/v2\/posts\/83\/revisions\/88"}],"wp:attachment":[{"href":"https:\/\/www.eversholt.org.uk\/blog\/wp-json\/wp\/v2\/media?parent=83"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.eversholt.org.uk\/blog\/wp-json\/wp\/v2\/categories?post=83"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.eversholt.org.uk\/blog\/wp-json\/wp\/v2\/tags?post=83"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}